martin collins 1 Posted July 9, 2020 Share Posted July 9, 2020 I bought this about a year ago and have just got round to pulling all the old Skyleader rx and servos out of it to put modern 2.4 stuff in. It has a 2 stroke i.c in it which is coming out to be replaced by an electric set up. The airframe is very light for it`s size and should make a nice flying model, my question is c of g, i have measured where it is on the current set up as it has obviously flown as is so that is my starting point but i have looked at the Gordon Whitehead 72" version and it is much further forward on that. This model is not built from that plan, the tailplane construction is much lighter on this and has no sheeting in the centre of it. I see on Sarik`s website that David Smith did a 73" one and it is on the X List plans list, the plan is nearly £30 so i don`t wish to purchase it unless i know my model IS built from that plan but i would be very interested to know where the c of g is on that. Can anyone help in any way c of g wise? Many thanks for any help given. Edited By martin collins 1 on 09/07/2020 11:47:14 Quote Link to comment Share on other sites More sharing options...
Stumps Posted July 9, 2020 Share Posted July 9, 2020 Could it be from the Hawker Hind plan that Sarik do ~ RSK1707? Quote Link to comment Share on other sites More sharing options...
martin collins 1 Posted July 9, 2020 Author Share Posted July 9, 2020 How did i miss that!!, Might well be but know way of finding out unless i get a look at the plan......... However, i think this must be much lighter built, i haven`t removed the engine yet but i would say it looks around a .60 two stroke size. Edited By martin collins 1 on 09/07/2020 12:01:46 Quote Link to comment Share on other sites More sharing options...
Eric Robson Posted July 9, 2020 Share Posted July 9, 2020 Just a thought, it does not matter how heavy or how light the model is the c of g should be in the same place. Unless the wing positions are not the same on one model as the ones on the plan you have. Eric r. Quote Link to comment Share on other sites More sharing options...
martin collins 1 Posted July 9, 2020 Author Share Posted July 9, 2020 I agree Eric but this has obviously been flown a lot and on this engine as the holes are only large enough to fit this size. The cord of the wing is 11.5" and the two points are 1.5" apart, not a small margin........... Quote Link to comment Share on other sites More sharing options...
charlie holdford Posted September 29, 2020 Share Posted September 29, 2020 Hi Martin The Sarik plan RC 1538 73" plan also has a 1/16th central sheet in the tail plane and rudder. But as its a plan the builder can do what they like! The Main wing cord is just under 12" The c of g is marked as exactly halfway between the cabane struts of the top wing As an aside the plan also shows it as a two seat bomber not the trainer as you have. Good luck Quote Link to comment Share on other sites More sharing options...
Robin Colbourne Posted September 29, 2020 Share Posted September 29, 2020 There is always the possibility if built from a plan that the builder redesigned the tail with a much lighter structure, if he was planning to put a lighter engine in from the start. Its a very nice looking model anyway! The full size Hart on which its modelled has an interesting history! Hawker Hart K4972 Timeline Quote Link to comment Share on other sites More sharing options...
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