Merlin spit Posted December 30, 2010 Share Posted December 30, 2010 after much reading ive decided to use two a123s with a switch each for redundancy .now i know the opinon is you can use these a123s with out regulators.but im looking at using the diode to drop voltage a little and protect against the unlikely of a short in one battery. now i need to know where and what ones to get? i presume something that's 8A capable would be fine. Quote Link to comment Share on other sites More sharing options...
GONZO Posted December 30, 2010 Share Posted December 30, 2010 One of THESE from Maplins ????? Quote Link to comment Share on other sites More sharing options...
Former Member Posted December 30, 2010 Share Posted December 30, 2010 [This posting has been removed] Quote Link to comment Share on other sites More sharing options...
Paul Adams Posted December 31, 2010 Share Posted December 31, 2010 If you put diodes in the feed from each battery, you will not need a switch as the diodes will only supply the voltage from the highest voltage battery to the receiver / circuit / motor. Remember however that you will need to add a separate charging lead to each battery which does not pass through the diode, as the diode will be reverse biased to the charging current. Quote Link to comment Share on other sites More sharing options...
Merlin spit Posted December 31, 2010 Author Share Posted December 31, 2010 thanks guys ,just for clarification the diodes should be soldered into the posstive or negative wires? i presume putting the diode the receiver side of the switch will alow me to charge via the charge socket on the switch Quote Link to comment Share on other sites More sharing options...
GONZO Posted December 31, 2010 Share Posted December 31, 2010 Part 1/ Diodes in +Ve leads. As you are useing a two switch arrangment feed the Rx at each end of the servo connector block to distribute the load (with Y leads if required). Part2 / Yes. Quote Link to comment Share on other sites More sharing options...
Vecchio Austriaco Posted December 31, 2010 Share Posted December 31, 2010 every diode will reduce the voltage for 0.7 volts. (silicium - which are most common these dauys) so if you need 2 volts reduction put 3iodes in series (2.1 volts drop) cheers VA - only 2 hours 5 mins to 2011 here! Quote Link to comment Share on other sites More sharing options...
Former Member Posted January 1, 2011 Share Posted January 1, 2011 [This posting has been removed] Quote Link to comment Share on other sites More sharing options...
Bob Moore Posted January 2, 2011 Share Posted January 2, 2011 I wouldn't worry about reverse current unless you are going to leave it for a very very long period. Months and months.The reverse current of the Maplin diode linked is 5 uA. 5 micro amps. ie 5 millionths of an amp. Or 1/200 of a milliamp. I would think the natural discharge rate of the batteries would be far more than than that? Quote Link to comment Share on other sites More sharing options...
Ultymate Posted January 2, 2011 Share Posted January 2, 2011 Everyone I know whose using A123s does so without any sort of voltage regulation, this seems to be one of the main attractions along with the fact that they can be charged at extremely high charge rates Quote Link to comment Share on other sites More sharing options...
crispin church Posted November 8, 2011 Share Posted November 8, 2011 i have used A123 2cell without any cut down for over 2 years without any problems on 35meg and 2.4 gig just one thing make sure you balance charge them often Quote Link to comment Share on other sites More sharing options...
Phil 9 Posted November 8, 2011 Share Posted November 8, 2011 what about a regulating switchhobby king power boxEdited By Phil B on 08/11/2011 19:49:49 Quote Link to comment Share on other sites More sharing options...
fly boy3 Posted November 8, 2011 Share Posted November 8, 2011 Excuse my lack of knowledge but what does " dual power redundancy" actually mean. Cheers Quote Link to comment Share on other sites More sharing options...
Phil 9 Posted November 8, 2011 Share Posted November 8, 2011 FB3 it just means two receiver batteries (dual power) that are a back up for each other. ie if one fails the other will still supply power. (one pack is redundant at any one time) Quote Link to comment Share on other sites More sharing options...
fly boy3 Posted November 8, 2011 Share Posted November 8, 2011 Thanks Phil, I think this type of set up is normal for the LMA boys ?. CheersEdited By fly boy3 on 08/11/2011 20:48:04 Quote Link to comment Share on other sites More sharing options...
Steve Hargreaves - Moderator Posted December 6, 2011 Share Posted December 6, 2011 Posted by Phil B on 08/11/2011 19:49:10: what about a regulating switchhobby king power box Edited By Phil B on 08/11/2011 19:49:49 Those units look exactly the same to me.....can it really be that there are two factories turning out identical looking units? Or are those Powerbox stickers just mightily expensive........ Quote Link to comment Share on other sites More sharing options...
Martin Harris - Moderator Posted December 6, 2011 Share Posted December 6, 2011 It wouldn't be the first example of badge engineering - or of cloning. Literally a case of pay your money and take your choice unless an insider spills the beans... Quote Link to comment Share on other sites More sharing options...
Bob Cotsford Posted December 6, 2011 Share Posted December 6, 2011 the Powerbox one has the facility to change the cutover voltage to suit LiFe, the HK one doesn't. The PB one also claims to use separate regulators and comparators for each battery where 'others use a single regulator'. Quote Link to comment Share on other sites More sharing options...
Steve Hargreaves - Moderator Posted December 6, 2011 Share Posted December 6, 2011 You could well be right Bob.....obviously I don't know what goes into either of them.....the HK description hints at two regulators.....yet even if the HK version only has one regulator against the two in the Powerbox unit so we double the price of the HK unit to 28USD to pay for another regulator that's still a heck of a difference!!! But I do think its intriguing that the two units look exactly the same.....same type of LEDs & pushbuttons etc.....Of course HK could have simply copied the design of the PowerBox one...... Quote Link to comment Share on other sites More sharing options...
Bob Cotsford Posted December 6, 2011 Share Posted December 6, 2011 or had it made in the same factory! Quote Link to comment Share on other sites More sharing options...
Stephen O'Neill Posted November 29, 2012 Share Posted November 29, 2012 I have just purchased some 6A diodes to reduce the voltage from my 123 Rx batteries. I was expecting to get a 0.7V reduction across the diode but only getting a 0.2V. Please excuse my lack of knowledge on this subject but I would welcome some guidance on where I am going wrong? The markings on my silicon diodes are: 6A100 A38 Quote Link to comment Share on other sites More sharing options...
michael cawood Posted November 29, 2012 Share Posted November 29, 2012 are you measuring the open circuit voltage. i think you need to be pulling power i.e. connected to something to get the full drop of 0.7v. Quote Link to comment Share on other sites More sharing options...
Stephen O'Neill Posted November 29, 2012 Share Posted November 29, 2012 Hi Miichael, you were absolutely right. I completely forgot about measuring the voltage with everything connected up, thanks Quote Link to comment Share on other sites More sharing options...
Peter Beeney Posted November 29, 2012 Share Posted November 29, 2012 Stephen, - I’m afraid I don’t recognise that number, do you know exactly the specification of your diodes? Also have you any means of checking your voltmeter? Any unexpected results, and it’s always a good idea to check the measuring instruments first, on the very odd occasion that can save a lot of flying time! After doing a very quick check, I came up with the following results on a couple of diodes, the forward volt drop measured directly across the diode with varying loads. A standard 6A silicon, P600A. Open circuit, 0.0093V. 5mA load, 0.6671V. 1A, 0. 8159V. A Schottky 16A MBRF 1645. Open circuit, 0.0001V 5mA load, 0.2578V 1A, 0.3815V. Any other similar pair will always give slightly different readings. This is one of the reasons they don’t like sharing the load when connected in parallel; and the forward drop is variable with the current flow. I do know that a 1A diode, when carrying a current of 1A, can drop up to at least 1 volt across the connections. In very general terms, as you imply, the forward drop for a silicon is 0.6 - 0.7 volt, whilst that of a Schottky is around the 0.2 volt mark. So is it perhaps possible you have Schottky diodes? Everything else being equal, I think it’s unlikely that you will get any standard silicon diodes with a forward volt drop as low as 0.2 volts… PB Quote Link to comment Share on other sites More sharing options...
Stephen O'Neill Posted November 29, 2012 Share Posted November 29, 2012 Hi Peter and thanks for your input.As always, you have come out with some very good information. The only spec info I have is 6A 1000V however the shop I bought them from is a local electronics supplier with a good reputation. I subsequently took the measurements with the receiver and servos connected up and it had the desired effect with a reading of 6.58V and 5.86V before and after the diode respectively. I have not had my tester calibrated but I expect it is near enough the mark as it is a new Graupner clamp meter. I will double check with a new field tester I have and let you know. Again, many thanks gents! Steve Quote Link to comment Share on other sites More sharing options...
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